An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm The size of the image is

9.2 cm

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10.5 cm

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5.6 cm

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7.5 cm

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Solution

The correct option is D 7.5 cm
R=-30 cm $\Rightarrow$ f=-15 cm
O=+2.5 cm,u=-10 cm

By mirror formula $\frac{1}{- 15} = \frac{1}{v} + \frac{1}{(- 10)} \Rightarrow v = 20 c m .$
Also $\frac{I}{O} = \frac{v}{u} \Rightarrow \frac{I}{(+ 2.5)} = \frac{30}{(- 10)} \Rightarrow I = + 7.5 c m .$

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An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm The size of the image is

The correct option is D 7.5 cmR=-30 cm ⇒ f=-15 cm O=+2.5 cm,u=-10 cm By mirror formula 1−15=1v+1(−10)⇒v=20 cm. Also IO=vu⇒I(+2.5)=30(−10)⇒I=+7.5 cm.

The correct option is D 7.5 cm
R=-30 cm $\Rightarrow$ f=-15 cm
O=+2.5 cm,u=-10 cm

By mirror formula $\frac{1}{- 15} = \frac{1}{v} + \frac{1}{(- 10)} \Rightarrow v = 20 c m .$
Also $\frac{I}{O} = \frac{v}{u} \Rightarrow \frac{I}{(+ 2.5)} = \frac{30}{(- 10)} \Rightarrow I = + 7.5 c m .$