An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm The size of the image is

9.2 cm

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10.5 cm

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5.6 cm

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7.5 cm

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Solution

The correct option is D 7.5 cm
$R = - 30 c m \Rightarrow f = - 15 c m$
O = +2.5 cm, u =-10 cm
By mirror formula $\frac{1}{- 15} = \frac{1}{v} + \frac{1}{(- 10)} \Rightarrow v = 30 c m .$
Also $\frac{I}{O} = - \frac{v}{u} \Rightarrow \frac{I}{(+ 2.5)} = - \frac{30}{(- 10)} \Rightarrow I = 7.5 c m$ .

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An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm The size of the image is

The correct option is D 7.5 cm R=−30cm⇒f=−15cm O = +2.5 cm, u =-10 cm By mirror formula 1−15=1v+1(−10)⇒v=30cm. Also IO=−vu⇒I(+2.5)=−30(−10)⇒I=7.5cm.

The correct option is D 7.5 cm
$R = - 30 c m \Rightarrow f = - 15 c m$
O = +2.5 cm, u =-10 cm
By mirror formula $\frac{1}{- 15} = \frac{1}{v} + \frac{1}{(- 10)} \Rightarrow v = 30 c m .$
Also $\frac{I}{O} = - \frac{v}{u} \Rightarrow \frac{I}{(+ 2.5)} = - \frac{30}{(- 10)} \Rightarrow I = 7.5 c m$ .