An object 4 cm high is placed at a distance of 10 cm from a convex mirror of radius of curvature 30 cm. Find the image distance.

6 cm

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10 cm

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Solution

The correct option is A 6 cm
Object distance, $u = - 10 c m$
Focal length,
$f = R / 2$
$f = + 30 / 2 c m$
$f = + 15 c m$

Using mirror formula:
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} + \frac{1}{- 10} = \frac{1}{15}$
$v = 6 c m$

So, the image distance is + 6 cm.

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An object 4 cm high is placed at a distance of 10 cm from a convex mirror of radius of curvature 30 cm. Find the image distance.

The correct option is A 6 cmObject distance, u=−10 cm Focal length, f=R/2 f=+30/2 cm f=+15 cm Using mirror formula: 1v+1u=1f 1v+1−10=115 v=6 cm So, the image distance is + 6 cm.

The correct option is A 6 cm
Object distance, $u = - 10 c m$
Focal length,
$f = R / 2$
$f = + 30 / 2 c m$
$f = + 15 c m$

Using mirror formula:
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} + \frac{1}{- 10} = \frac{1}{15}$
$v = 6 c m$

So, the image distance is + 6 cm.