Dear Student,
object distance, u=−25 cmfocal length, f=−15 cmheight of object, h=4 cm1v+1u=1f1v+1(−25)=1(−15)1v=125−1151v=3−575image distance, v=−752=−37.5 cmmagnification, m=h'h=−vuh'4=−(−37.5)(−25)height of image, h'=−15025=−6 cmm=h'hm=−64=−1.25So, the image is real and inverted as m is negative and magnified as h'>h.
Regards