Question 10 An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.
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Solution
Object distance, u = - 25 cm focal length, f = 10 cm height of the object, h0 = 5 cm Substituting in the lens formula, 1f=1v−1u 1v=1f+1u 1v=110−125 1v=350 v=503cm = 16.7 cm The image is real and inverted at a distance of 16.7 cm from the lens on the opposite side. Magnification, m=hih0=vu hi5=16.7−25 hi=16.7−25×5= -3.34 cm The image is formed at a distance 16.7 cm from the lens on the other side of the lens. The image is inverted and diminished.