An object 5cm is placed at a distance of 20cm in front of a convex mirror of radius of curvature 30cm. Find the position of the image, its nature and size.
Open in App
Solution
Formula:
1v+1u=1f
Given,
1v+1(−20)=115
1v=760⇒v=607
v=8.57≈8.6cm
The image is formed behind the mirror at a distance of 8.6cm
m=h2h1=−vu
→h25=−8.5720
∴h2=2.175cm
Thus the image is 2.175cm high, virtual and erect.