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Question

an object ABED is placed in front of a concave mirror beyond the center of curvature C as shown in figure. State the shape of the image
159407.png

A
|mAB|<1 and |mED|<1
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B
|mAB|>1 and |mED|<1
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C
|mAB|<1 and |mED|>1
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D
|mAB|>1 and |mED|>1
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Solution

The correct option is A |mAB|<1 and |mED|<1
Object is placed beyond C. Hence, the image will be real and if will lie between C and F. Further u, and v are negative, hence the mirror formula will become
1v+1u=1f
1v+1u=1f=ufuf or v=f1(f/u)
Now uAB>uED
vAB>vED
|mAB|<|mED|(as m=vu)
Therefore, shape of the image will be as shown in figure.
Also note that, vAB<uAB and vED<uED,
So, |mAB|<1 and |mED|<1.
1588396_159407_ans_bf36a7f7a8e648a6a28377cda9f44bae.jpg

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