Question

An object accelerates from rest to a velocity $30m/s$ in $10s,$ then find distance covered by the object during next $10s.$

Answer 1

Initial velocity $u=0$
Final velocity $v=30m/s$
Time, $t=10\sec$
$v=u+at$
$30=0+a\times 10$
$30=10a$
$a=\frac{30}{10}=3m/s^2$
for next $10\sec ,$ initial velocity $=30m/s$
$s=ut+\frac{1}{2}a{t}^2$
$=30\times 10+\frac{1}{2}\times 3\times {\left(10\right)}^2$
$=300+1.5\times 100$
$=300+150$
$=450m$