The correct option is D 4^i m/s
Given:
Velocity of object with respect to ground along x-axis, VOx=4 m/s
Mirror's velocity with respect to ground, along x-axis, Vmx=5cos37∘=+4 m/s, and
Mirror's velocity with respect to ground, along y-axis,
Vmy=5sin37∘=+3 m/s
Let the image's velocity with respect to ground be VI.
Velocity of object with respect to mirror along x-axis is given by
VOmx=VOx−Vmx=4−4=0
Similarly, velocity of object with respect to mirror along y-axis is given by
VOmy=VOy−Vmy=0−3=−3 m/s
Velocity of image w.r.t mirror along x-axis is given as,
VImx=−VOmx
∴VImx=0 m/s
Similarly, velocity of image w.r.t mirror along y-axis is given as,
VImy=VOmy
∴VImy=−3 m/s
Lets the velocity of image with respect to ground alongx-axis and y-axis are VIx and VIy respectively.
Using the concept of relative velocity,
VImx=VIx−Vmx
⇒VIx=VImx+Vmx=0+4=4 m/s
Similarly,
VIy=VImy+Vmy=−3+3=0 m/s
∴VI=VIx^i+VIy^j=4^i m/s
Hence, correct option is (d).
Ans D