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Relating Circular Motion to SHM

An object has...

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An object has velocity v=(2i^+4j^)m/s at time t=0s.If undergoes a constant acceleration a=(i^-3j^) m/s2 for t=4s then Find the Co ordinates of the object at t =0seconds (Why while putting value we put here t=4 not 0)

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Q. An object have a velocity

\to v = (^i +^j) m / s

t = 0

. It undergoes a constant acceleration

a = (^i - 2^j) m s^{- 2}

4

second. The magnitude of velocity at the end of

4 s

Q. If the relation between acceleration and time for an object is given by

a = 2 t + 4 t^{2}

.
Calculate the position of object from the origin at

t = 4 s

t = 0, v = 0, x = 0

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