An object has velocity v- - -1- w-r-t- ground- An observer moving with constant velocity v- - -0- w-r-t- ground measures the velocity of the object as v- - -2- The magnitudes of three velocities are related by-

The correct option is A v _ 1 ≤ v _ 2 + v _0 v⃗_2 =v⃗_1 v⃗_0, v⃗_2+v⃗_0=v⃗_1 From the law of triangle, we can draw the velocity vector diagram.From ...

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Standard XII

Physics

Uniform and Non Uniform

An object has...

Question

An object has velocity $_{1}$ w.r.t. ground. An observer moving with constant velocity $_{0}$ w.r.t. ground measures the velocity of the object as $_{2}$ . The magnitudes of three velocities are related by:

v_{0} \geq v_{1} + v_{2}

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v_{1} \leq v_{2} + v_{0}

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v_{2} \geq v_{1} + v_{0}

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All of the above

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Solution

The correct option is A $v_{1} \leq v_{2} + v_{0}$
${\to v}_{2} = {\to v}_{1} - {\to v}_{0}, {\to v}_{2} + {\to v}_{0} = {\to v}_{1}$
From the law of triangle, we can draw the velocity vector diagram.
From triangle property, sum of two sides $\geq$ third side
So $v_{1} \leq v_{0} + v_{2}$

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An object has velocity →v1 w.r.t. ground. An observer moving with constant velocity →v0 w.r.t. ground measures the velocity of the object as →v2. The magnitudes of three velocities are related by:

The correct option is A v1≤v2+v0→v2=→v1−→v0,→v2+→v0=→v1From the law of triangle, we can draw the velocity vector diagram.From triangle property, sum of two sides ≥ third side So v1≤v0+v2

An object has velocity $_{1}$ w.r.t. ground. An observer moving with constant velocity $_{0}$ w.r.t. ground measures the velocity of the object as $_{2}$ . The magnitudes of three velocities are related by:

The correct option is A $v_{1} \leq v_{2} + v_{0}$
${\to v}_{2} = {\to v}_{1} - {\to v}_{0}, {\to v}_{2} + {\to v}_{0} = {\to v}_{1}$
From the law of triangle, we can draw the velocity vector diagram.
From triangle property, sum of two sides $\geq$ third side
So $v_{1} \leq v_{0} + v_{2}$