An object having a velocity $4.0 m / s$ is accelerated at the rate of $1.2 m / s^{2}$ for $5.0 s .$ Find the distance travelled during the period of acceleration

35 m

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55 m

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60 m

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20 m

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Solution

The correct option is B $35 m$
Given data,
$v = 4 m / s,$
$a = .2 m / s^{2},$
$t = 5 s$
$s = u t + \frac{1}{2} a t^{2}$
$s = 4 \times 5 + \frac{1}{2} \times 25 \times 1.2 = 35 m$

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An object having a velocity 4.0m/s is accelerated at the rate of 1.2m/s2 for 5.0s. Find the distance travelled during the period of acceleration

The correct option is B 35mGiven data,v=4m/s,a=.2m/s2,t=5ss=ut+12at2s=4×5+12×25×1.2=35m

An object having a velocity $4.0 m / s$ is accelerated at the rate of $1.2 m / s^{2}$ for $5.0 s .$ Find the distance travelled during the period of acceleration

The correct option is B $35 m$
Given data,
$v = 4 m / s,$
$a = .2 m / s^{2},$
$t = 5 s$
$s = u t + \frac{1}{2} a t^{2}$
$s = 4 \times 5 + \frac{1}{2} \times 25 \times 1.2 = 35 m$