Question

An object is allowed to roll down the incline starting from rest. All are uniform and have same mass and radius.
Column-I Column-II

Answer 1

Thin hollow cylinder has MI $M{R}^2$ which more than others listed.
A->4
Since MI for hollow cylindrical shell is maximum, it will experience the maximum torque for a given angular acceleration.( $\tau =I\alpha$)
B->4
Solid sphere has the least MI, hence, it will have the maximum linear speed at the bottom of the incline.
C->1
Acceleration $a=\frac{g\sin \theta }{1+\frac{k^2}{r^2}}$
Hollow cylinder has the least acceleration.
$v=\sqrt{\frac{2gh}{1+\frac{k^2}{r^2}}}$
Time of descent $t\propto \frac{1}{\sqrt{1+\frac{k^2}{r^2}}}$
since k is more for hollow cylinder, it will take least time to reach the bottom of the inclined plane.