An object is being thrown at a speed of 20m/s in a direction 45^0 above horizontal . he time taken by the object to return to same level is (1) 20/g (2) 20g (3) 20\sqrt2 /g (4) 20\sqrt{2 } g

Open in App

Solution

Suggest Corrections

Similar questions

Q. An object is launched at a velocity of

20 m / s

in a direction making an angle of

30^{\circ}

upward with the horizontal. What is the total flight time (between launch and touching the ground) of the object?
(Take

g = 10 m / s^{2}

)

Q. A body is thrown with speed 20 m/s vertically upwards,if will return to thrower's hand after a time

(g = 10 m / s^{2})

A cricket ball is thrown at a speed of $28 m s^{- 1}$ in a direction $30^{0}$ above horizontal. Calculate
a) The maximum height
b) The time taken by the ball to return to the same level.
c) The distance from the thrower to the point where ball returns to the same level.

A ball is thrown vertically upwards at speed of $20 m s^{- 1}$ . Find the time taken by the ball to reach back to the original position. [Take acceleration die to gravity, $g = 10 m s^{- 2}$ ]

A boy throws a ball upwards with velocity $v_{0}$ = 20 m/s . The wind imparts a horizontal acceleration of 4 m/ $s^{2}$ to the left.

The angle $θ$ at which the ball must be thrown so that the ball returns to the boy's hand is ( g = 10m/ $s^{2}$ )

Join BYJU'S Learning Program