The correct option is C 4 J
Given, force →F=4^i−2^j
Displacement vector →ds=dx^i+dy^j
workdone (W)=∫→F.→ds=∫(3,4)(0,0)(4^i−2^j).(dx^i+dy^j)
W=∫(3,4)(0,0)4dx−2dyW=4x|(3)(0)−2y|(4)(0)
W=4(3−0)−2(4−0)=4 J
Alternate:
From the question we have displacement as
→S=3^i+4^j
Given, force →F=4^i−2^j
From the definition of workdone, we have
W=→F⋅→S
⇒ W=(4^i−2^j)⋅(3^i+4^j)=12−8=4 J