An object is displaced from position vector →r1=(2^i+3^j)m to →r2=(4^i+6^j)m under the action of a force →F=(3x2^i+2y^j)N. Find the work done by this force.
A
17J
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B
83J
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C
10J
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D
80J
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Solution
The correct option is B83J Wprk done by variable forceW=r2∫r1→F.→dr=r2∫r1(3x2^i+2y^j).(dx^i+dy^j+dz^k) =r2∫r1(3x2dx+2ydy)=[x3+y2](4,6)(2,3)=83J