An object is dropped from rest at a height of $150 m$ and simultaneously another object is dropped from rest at a height of $100 m$ . What is the difference in their heights after $2 s$ if both the objects drop with same acceleration?

0 m

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50 m

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20 m

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40 m

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Solution

The correct option is C $50 m$
Initial difference in height $Δ h = 150 m - 100 m = 50 m$
Distance for each body with time is given by: $s = u t + \frac{1}{2} a t^{2}$
In the above question both the object are released from rest, so initial velocity is: $u = 0$
Since the object are dropped at same time, so decrease in height is,
$s_{1} = s_{2} = \frac{1}{2} g t^{2} = 20 m$
Height of first body after 2 s, $h_{1} = 150 - 20 = 130 m$
Height of second body after 2 s, $h_{2} = 100 - 20 = 80 m$
Difference in heights $= 50 m$

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An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height of 100 m. What is the difference in their heights after 2 s if both the objects drop with same acceleration?

An object is dropped from rest at a height of $150 m$ and simultaneously another object is dropped from rest at a height of $100 m$ . What is the difference in their heights after $2 s$ if both the objects drop with same acceleration?