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Question

An object is dropped from rest at a height of 150 m and simultaneously another object is dropped from rest at a height of 100 m. What is the difference in their heights after 2 s if both the objects drop under the same acceleration? How does the difference in heights vary with time?

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Solution

Initial difference in height = (150100) m=50 m
Distance travelled by first body in 2 s=h1=0+12g(2)2=2g
Distance travelled by another body in 2 s=h2=0+12g(2)2=2g
After 2 s, height at which the first body will be = h1=1502g
After 2 s, height at which the second body will be = h2=1002g
Thus, after 2 s, difference in height =1502g(1002g)
=50 m = initial difference in height.
Thus, difference in height does not vary with time.

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