An object is held 25 cm away from a converging lens of focal length 10 cm. Find the position of the image.

6.67 cm

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- 6.67 cm

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16.67 cm

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- 16.67 cm

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Solution

The correct option is C 16.67 cm
$u = - 25 cm, f = + 10 cm$

Applying lens formula-
$- \frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{10} - \frac{1}{25} = \frac{3}{50}$
$v = \frac{50}{3} = 16.67 cm$

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(1) An object of size 7 cm is placed at 25 cm in front of concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed, so that we can get a sharp and clear image. Find nature and size of the image.

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An object is held 25 cm away from a converging lens of focal length 10 cm. Find the position of the image.

The correct option is C 16.67 cm u=−25 cm, f=+10 cm Applying lens formula- −1u+1v=1f 1v=1f+1u=110−125=350 v=503=16.67 cm

The correct option is C 16.67 cm
$u = - 25 cm, f = + 10 cm$

Applying lens formula-
$- \frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{10} - \frac{1}{25} = \frac{3}{50}$
$v = \frac{50}{3} = 16.67 cm$