You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Image Formation by Convex Lens

An object is ...

Question

An object is held 25 cm away from a converging lens of focal length 10 cm. Find the position of the image.

6.67 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

- 6.67 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

16.67 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

- 16.67 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 16.67 cm
$u = - 25 cm, f = + 10 cm$

Applying lens formula-
$- \frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{10} - \frac{1}{25} = \frac{3}{50}$
$v = \frac{50}{3} = 16.67 cm$

Suggest Corrections

Similar questions

Q. An object is held

20 c m

away from a converging lens of focal length

10 c m

. Find the position of the image formed.

Q. An object

5 c m

in length is held

25 c m

away from converging lens of focal length

10 c m

. Draw the ray diagram and find the position, size and nature of the image formed.

Question 10
An object 5 cm in length is held 25 cm away from a converging lens of focal length 10 cm. Draw the ray diagram and find the position, size and the nature of the image formed.

Q. An object of height

5 c m

is held

20 c m

away from converging lens of focal length

10 c m

,Find the position, nature and size of the image formed.

Solve:

(1) An object of size 7 cm is placed at 25 cm in front of concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed, so that we can get a sharp and clear image. Find nature and size of the image.

(2) An object of height 5 cm is held 20 cm away from converging lens of focal length 10 cm. Find the position, nature and size of the image formed.

(3) An object is placed at a distance of 10 cm from a convex lens of focal length 12 cm. Find the position and nature of the image.

Join BYJU'S Learning Program

An object is held 25 cm away from a converging lens of focal length 10 cm. Find the position of the image.

The correct option is C 16.67 cm u=−25 cm, f=+10 cm Applying lens formula- −1u+1v=1f 1v=1f+1u=110−125=350 v=503=16.67 cm

The correct option is C 16.67 cm
$u = - 25 cm, f = + 10 cm$

Applying lens formula-
$- \frac{1}{u} + \frac{1}{v} = \frac{1}{f}$
$\frac{1}{v} = \frac{1}{f} + \frac{1}{u} = \frac{1}{10} - \frac{1}{25} = \frac{3}{50}$
$v = \frac{50}{3} = 16.67 cm$