Question

An object is kept 5 cm in front of a concave mirror of focal length 15 cm. What will be the nature of the image?

• A. virtual, not magnified
• B. virtual, magnified
• C. real, not magnified
• D. real, magnified

Answer 1

The correct option is B virtual, magnified

Using $\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$

$\therefore$ $\frac{1}{v}+\frac{1}{-5}=\frac{1}{-15}$

$⟹v=+7.5cm$

So image is formed behind the mirror, thus it is virtual.

Magnification $m=\frac{-v}{u}=\frac{-7.5}{-5}=1.5$

So, magnified image is formed.