Question

An object is kept at 0.200 m from a double convex lens or biconvex lens of focal length $0.0150m$ .The position of the image is

• A. 0.0162m
• B. 0.600 m
• C. 8.00 m
• D. 11.6 m

Answer 1

The correct option is A 0.0162m

$\frac{1}{v}-\frac{1}{u}=\frac{1}{f}$

$\Rightarrow \frac{1}{v}+\frac{1}{0.2}=\frac{1}{0.015}$

$\Rightarrow \frac{1}{v}=\frac{1000}{15}=\frac{10}{2}$

$\Rightarrow \frac{1}{v}=\frac{2000-150}{30}$

$\Rightarrow \frac{1}{v}=\frac{1850}{30}$

$\Rightarrow v=\frac{30}{1850}=\frac{3}{185}=0.0162$

Hence,

option $\left(A\right)$ is correct answer.