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Question

An object is kept at x = 0, force on the object is F(constant) from t = 0. Friction coefficient varies as μ=cx. Find the ratio of the maximum value of friction force and magnitude of static friction just after the block stopped.
794815_fd15143c1b3c431b946834069797fc8c.png

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Solution

x=2y
When frictional force equal to F
f1=μMg=cyMg=F
y=FcMg
Then when block stops then displacement is 2y
force of friction is
fmax=μMg=2y(cMg)
fmax=2F


985086_794815_ans_3a4200a6f6664e0d9395e73b103a2654.png

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