Question

An object is moving along a straight line whose velocity-time graph is given below:
What will be the ratio of the distance travelled to the displacement of object from $t=0$ and $t=5$ sec?

• A. $1:3$
• B. $2:1$
• C. $3:1$
• D. $6:1$

Answer 1

The correct option is B $2:1$

Distance = Area of (1) + Area of (2) + Area of (3)

$=\frac{1}{2}\times 1\times 40+\frac{1}{2}\times 2\times 40+\frac{1}{2}\times 2\times 20$

$=20+40+20$

$=80$

Displacement = Area of (1) + Area of (2) - Area of (3)

$=20+40-20$

$=40$

$=2:1$