An object is moving in a straight-line path has a velocity of 40m/s at some instant. After 5s, its velocity changed to 30m/s. What is the average acceleration of the ball during this time interval?
A
2m/s2
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B
−2m/s2
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C
−4m/s2
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D
4m/s2
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Solution
The correct option is B−2m/s2 Average acceleration of the object is given by ¯a=vf−vit where, vf is the final velocity of the object, vi is the initial velocity of the object and t is the time taken by object to attain the final velocity from initial. Hence, average acceleration is given by ¯a=30−405=−2m/s2