Question

An object is moving vertically upward at speed of $V$ as shown in figure. Velocity of image from mirror inclined at angle of ${37}^{\circ }$ from horizontal is

• A. ($\frac{24}{25}\hat{i}+\frac{7}{25}\hat{j}$)V
• B. ($\frac{7}{25}\hat{i}-\frac{24}{25}\hat{j}$)V
• C. ($\frac{7}{25}\hat{i}+\frac{24}{25}\hat{j}$)V
• D. ($\frac{24}{25}\hat{i}-\frac{7}{25}\hat{j}$)V

Answer 1

The correct option is D ($\frac{24}{25}\hat{i}-\frac{7}{25}\hat{j}$)V




$V_x=\frac{24}{25}\text{V}$

$V_y=\frac{7}{25}\text{V}$

Therefore, net velocity of image $=(\frac{24}{25}\hat{i}-\frac{7}{25}\hat{j})\text{V}$