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Question

An object is moving with uniform acceleration. Its velocity after 5s is 25 m\s and after 8s is 34m/s. Find the distance travelled by the object in 12th second.

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Solution

V = u + at


After 5s

25 = u + 5a ——(1)


After 8s

34 = u + 8a ——(2)


Subtract equation (1) from equation (2)

34 - 25 = u + 8a - u - 5a

9 = 3a

a = 3 m/s^2


Substitute a = 3m/s^2 in equation (1)

25 = u + 5*3

u = 10 m/s


Distance travelled in 12th second

S = u + a(n - 1/2)

S = 10 + 3*(12 - 1/2)

S = 44.5m


Distance travelled in 12th second is 44.5m


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