Question

an object is placed 10cm in front of a convex mirror with a focal lenght of 15cm.Where will the image be formed ??what will be the nature of image

Answer 1

Dear Student

$$\begin{gathered} \frac{1}{v}+\frac{1}{u}=\frac{1}{f} \\ \frac{1}{v}-\frac{1}{10}=\frac{-1}{15} \\ \frac{1}{v}=\frac{-1}{15}+\frac{1}{10} \\ v=30cm \\ Imagewillbevirtual,erectanddimnished \end{gathered}$$