Question

An object is placed 12 cm to the left of a converging lens of focal length 8 cm. Another converging lens of focal length 6 cm is placed at a distance of 30 cm to the right of the first lens. Find the nature and position of the image?

Answer 1

Dear Student,

$$\begin{gathered} u=-12cm,f=8cm \\ imageformedbythefirstlensatv \\ \frac{1}{v}-\frac{1}{u}=\frac{1}{f} \\ \frac{1}{v}-\frac{1}{-12}=\frac{1}{8} \\ \frac{1}{v}=\frac{1}{8}-\frac{1}{12}=\frac{1}{24} \\ v=24cm \\ thisimageactasobjectforthelenstwo \\ u=-\left(30-24\right)=-6cm,f=6cm \\ \frac{1}{v}-\frac{1}{-6}=\frac{1}{6} \\ hencev=\infty \\ theimagewillformatinfinity \\ Regards \end{gathered}$$