Question

An object is placed $12cm$ to the left of a converging lens of focal length $8cm$. Another converging lens of $6cm$ focal length is placed at a distance of $30cm$ to the right of the first lens. The second lens will produce

• A. No image
  
• B. A real smaller image
• C. A real enlarged image
  
• D. A virtual enlarged image
  

Answer 1

The correct option is C A real enlarged image


We know that: $\frac{1}{f}=\frac{1}{v}-\frac{1}{u}$

Given: $u=-12cm,f=+8cm$



$\frac{1}{8}=\frac{1}{v}-\frac{1}{-12}$

Therefore $v=24cm$, i.e., image $A^{\prime }{B}^{\prime }$ is obtained $6cm$ before the lens $2$ or at the focus of lens $2$.
Final rays are parallel to each other, that means rays will meet at infinity.

Hence final image formed by lens $2$ will be real enlarged and it is obtained at infinity.

Hence, correct option is (c).