CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

An object is placed 15 cm from (a) a converging mirror, and (b) a diverging mirror, of radius of curvature 20 cm. Calculate the image position and magnification in each case.

Open in App
Solution

Case -1
It is a converging mirror, i.e. concave mirror.
Distance of the object 'u' = -15 cm
Radius of curvature of the mirror 'R' = -20 cm
Focal length of the mirror 'f' = R2 = -10 cm
We have to find the position of the image 'v' and its magnification 'M'.
Using the mirror formula, we get
1f=1u+1v1-10=1-15+1v1v=1-10+1151v=-110+1151v=-15150+101501v=-5150v=-30cmtheimagewillbeformatadistanceof 30cminfrontofconvergingmirror.magnification=-vum=-(-30)-15m=-2magnification=-2

Thus the image is real, inverted and large in size.
Case -2
Mirror is converging mirror i.e. convex mirror.
Distance of the object u = -15 cm
Radius of curvature of the mirror R = 20 cm
Focal length of the mirror f = R2 = 10 cm
We have to find the position of the image v = ?
Magnification = ?
Using themirrorformula, we get1f=1u+1v1f=1-15+1v110=1-15+1v1v=110+1151v=15150+101501v=251501v=16v=6 cmTherefore, the imagewilll form 6 cm behind the mirror.Using the magnification formula, we get m=-vum=-6-15m=0.4


Thus, the image is virtual, erect and small in size.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Image Formation by Spherical Mirrors - concept
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon