An object is placed $20 c m$ in front of a block of glass $10 c m$ thick and its farther surface is silvered. If the image is formed $23.2 c m$ behind the silvered face, find the refractive index of the glass.

Open in App

Solution

Given, Apparent depth = 23.2 cm

Real depth = 30cm

& we know that $μ = \frac{R e a l d e p t h}{a p p a r e n t d e p t h}$

$μ = \frac{30}{23.2}$

$μ = 1.29310$

Suggest Corrections

Similar questions

Q. an object is placed 30 cm(from the reflecting surface) in front of a block of glass 10 cm thick having its farther side silvered. the final image is formed at 23.2 cm behind the silvered face. The refractive index of glass is :

Q. One face of a rectangular glass plate of thickness 6 cm is silvered. an object is placed at a distance of 8 cm in front of the unsilvered face. Its image is formed 10 cm behind the silvered face. The refractive index of glass plate is :

Q. One face of a rectangular glass plate

6 c m

thick is silvered. An object held

8 c m

in front of the first face, forms an image

12 c m

behind the silvered face. The refractive index of the glass is:

One face of a rectangular glass plate 6 cm thick is silvered. An object held 8 cm in front of the first face, forms an image 12 cm behind the silvered face. The refractive index of the glass is :

Q. One face of a

6 cm

thick rectangular glass plate is silvered. An object held

8 cm

in front of the unsilvered face forms an image

10 cm

behind the silvered face. Find the critical angle for glass-air interface.
[consider two refractions and one reflection]

Join BYJU'S Learning Program

An object is placed 20 cm in front of a block of glass 10 cm thick and its farther surface is silvered. If the image is formed 23.2 cm behind the silvered face, find the refractive index of the glass.

Given, Apparent depth = 23.2 cmReal depth = 30cm& we know that μ=Realdepthapparentdepth μ=3023.2 μ=1.29310

An object is placed $20 c m$ in front of a block of glass $10 c m$ thick and its farther surface is silvered. If the image is formed $23.2 c m$ behind the silvered face, find the refractive index of the glass.

Given, Apparent depth = 23.2 cm

Real depth = 30cm

& we know that $μ = \frac{R e a l d e p t h}{a p p a r e n t d e p t h}$

$μ = \frac{30}{23.2}$

$μ = 1.29310$