An object is placed 5 cm from an convex air-glass interface of radius of curvature 10 cm as shown. If the refractive index of glass is 1.5, determine the location of image from the interface.

10 cm, left

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10 cm, right

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5 cm, left

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5 cm, right

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Solution

The correct option is A 10 cm, left
Given:
$u = - 5 c m$
$R = 10 c m$
$μ_{1} = 1$
$μ_{2} = 1.5$

Using refraction formula at spherical surface,
$\frac{μ_{2}}{v} - \frac{μ_{1}}{u} = \frac{μ_{2} - μ_{1}}{R}$
$\frac{1.5}{v} - \frac{1.0}{- 5} = \frac{1.5 - 1}{10}$
$\frac{1.5}{v} = \frac{0.5}{10} - \frac{1}{5}$
$v = - 10 c m$

The image is formed 10 cm left to the spherical surface.

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An object is placed 5 cm from an convex air-glass interface of radius of curvature 10 cm as shown. If the refractive index of glass is 1.5, determine the location of image from the interface.

The correct option is A 10 cm, leftGiven: u=−5 cm R=10 cm μ1=1 μ2=1.5 Using refraction formula at spherical surface, μ2v−μ1u=μ2−μ1R 1.5v−1.0−5=1.5−110 1.5v=0.510−15 v=−10 cm The image is formed 10 cm left to the spherical surface.