An object is placed at 30 cm in front of the convex lens of focal length 10 cm. Find out the image distance from lens.

– 10 cm

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+ 20 cm

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+ 15 cm

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– 20 cm

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Solution

The correct option is C
+ 15 cm

From Len's formula, $\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

f = + 10 cm (convex lens)

u = - 30 cm

$\frac{1}{v}$ + $\frac{1}{30}$ = $\frac{1}{10}$

$\frac{1}{v}$ = $\frac{1}{10}$ - $\frac{1}{30}$ = + $\frac{2}{30}$

v = + 15 cm

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An object is placed at 30 cm in front of the convex lens of focal length 10 cm. Find out the image distance from lens.

The correct option is C + 15 cm From Len's formula, 1v - 1u = 1f f = + 10 cm (convex lens) u = - 30 cm 1v + 130 = 110 1v = 110 - 130 = + 230 v = + 15 cm

The correct option is C
+ 15 cm

From Len's formula, $\frac{1}{v}$ - $\frac{1}{u}$ = $\frac{1}{f}$

f = + 10 cm (convex lens)

u = - 30 cm

$\frac{1}{v}$ + $\frac{1}{30}$ = $\frac{1}{10}$

$\frac{1}{v}$ = $\frac{1}{10}$ - $\frac{1}{30}$ = + $\frac{2}{30}$

v = + 15 cm