Question

An object is placed at a distance of 10 cm from a convex mirror of a focal length of 15 cm. Find the position and nature of the image.

Answer 1

Given:

The focal length $f=+15cm$

Object distance $u=-10cm$

Mirror type: convex

Finding the image distance from mirror formula:

We know that $\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$

$$\begin{gathered} \frac{1}{v}=\frac{1}{15}+\frac{1}{10} \\ \frac{1}{v}=\frac{5}{30} \\ v=+6cm \end{gathered}$$

The image is formed 6 cm behind the mirror; it is a virtual and erect image