Given, object distance, u = -15 cm and focal length, f = 20 cm
Let image distance be 'v'.
We know, 1f=1v−1u
120=1v+115
1v=120−115
⇒ v = -60 cm.
Four characteristics of the image formed by the lens are:
(i) The image is virtual.
(ii) The image is erect.
(iii) Image is formed at a distance of 60 cm on the same side of the lens as the object.
(iv) The image is an enlarged image.