The correct option is B The image formed is real.
Given :
Radius of curvature R = 0.6 m = 60 cm
Let f be the focal length
We know that
f=R2
f=30 cm
For a concave mirror, focal length is taken as negative
i.e f=−30 cm
So, formed image is virtual.
As
Object distance u=−20 cm
Let v be the image distance
Using mirror formula,
1f = 1v + 1u
1-30 = 1v + 1-20
⇒1v=1-30 + 120
⇒v=60cm
Positive sign of v indicates that image is virtual and as both u and v are with same sign, so, the image will be erect.