An object is placed at a distance of 20 cm from a convex lens of focal length 10 cm. The image is formed on the other side of the lens at a distance:

30 cm

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20 cm

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10 cm

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40 cm

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Solution

The correct option is B 20 cm
Apply lens formula,
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
Given, u = - 20 cm and f = 10 cm
$\frac{1}{10} = \frac{1}{v} - \frac{1}{- 20}$
$\Rightarrow v = 20 c m$

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Similar questions

A diverging lens, focal length $f_{1} = 20 cm$ is separated by 5 cm from a converging mirror, focal length $f_{2} = 10 cm$ . Where should an object be placed from the lens so that a real image is formed at the object itself ?

For an object placed at a distance 20 cm in front of a convex lens, the image is at a distance 20 cm behind the lens. The focal length of convex lens is :

(a) 20 cm (b) 10 cm (c) 15 cm (d) 40 cm

An object is placed at 30 cm in front of the convex lens of focal length 10 cm. Find out the image distance from lens?

Q. A convex lens forms an image at the distance

40 c m

on other side of the lens when an object which is placed at

40 c m

away from it . The object is then moved

10 c m

towards the lens then, where will be the image shift?

Q. Fill in the blank.

An object is placed at a distance of more than

40 c m

from a convex lens of focal length

20 c m

. The image formed is real, inverted and ______.

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An object is placed at a distance of 20 cm from a convex lens of focal length 10 cm. The image is formed on the other side of the lens at a distance:

The correct option is B 20 cmApply lens formula, 1f=1v−1u Given, u = - 20 cm and f = 10 cm 110=1v−1−20 ⇒v=20 cm

The correct option is B 20 cm
Apply lens formula,
$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$
Given, u = - 20 cm and f = 10 cm
$\frac{1}{10} = \frac{1}{v} - \frac{1}{- 20}$
$\Rightarrow v = 20 c m$