An object is placed at a distance of 30 cm. from a concave mirror. The magnification produced is 1/2. where should the object be placed to get the magnification of 1/3.
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Solution
U=−30
m=12
we know that
m=−VU
so V = 15
f=10
for m=13
−VU=13
V=−V3
1f=1V+1U
110=3−U+1U
U = -40
Therefore for magnification to be 13 the object must be placed 40cm upon in front of the mirror.