An object is placed at a distance of 40 cm in front of a concave mirror of focal length 15 cm. Where a screen should be placed in order to obtain a sharp image?

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Solution

Given: u = - 40 cm
f = - 15 cm
v=?

Using: 1/f = 1/v + 1/u

We have,
1/v = 1/-15 - 1/-40

1/v = -1/24

v = -24 cm

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An object is placed at a distance of 40 cm in front of a concave mirror of focal length 15 cm. Where a screen should be placed in order to obtain a sharp image?

Given: u = - 40 cm f = - 15 cm v=? Using: 1/f = 1/v + 1/u We have, 1/v = 1/-15 - 1/-40 1/v = -1/24 v = -24 cm

Given: u = - 40 cm
f = - 15 cm
v=?

Using: 1/f = 1/v + 1/u

We have,
1/v = 1/-15 - 1/-40

1/v = -1/24

v = -24 cm