Question

An object is placed at a distance of 8 cm from a convex mirror of focal length 12 cm. Find the position and nature of the image formed.

Answer 1

Dear Student

$$\begin{gathered} u=-8cm \\ f=+12cm(convexmirror) \\ v=? \\ weknow\frac{1}{v}+\frac{1}{u}=\frac{1}{f} \\ so\frac{1}{12}=\frac{1}{v}+\frac{1}{-8} \\ \Rightarrow \frac{1}{12}+\frac{1}{8}=\frac{1}{v} \\ \Rightarrow \frac{1}{v}=\frac{2+3}{24} \\ \Rightarrow \frac{1}{v}=\frac{5}{24} \\ \Rightarrow v=4.8cm \\ Imageformedbyconvexmirrorarealwaysvirtual,errectanddiminished \end{gathered}$$

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