An object is placed at the centre of curvature of a concave mirror. The distance between its image and the pole is:

equal to f

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between f and 2f

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equal to 2f

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greater than 2f

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Solution

The correct option is C equal to 2f
Given: $u = - 2 f$ $f = - f$ (concave mirror)
To find : $v$
Solution: From mirror formula
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} - \frac{1}{- 2 f} = \frac{- 1}{f}$
$\frac{1}{v} = \frac{- 1}{2 f}$
$v = - 2 f$

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Question 3
Under which of the conditions a concave mirror can form an image larger than the actual object?

(a) When the object is kept at a distance equal to its radius of curvature.
(b) When object is kept at a distance less than its focal length.
(c) When object is placed between the focus and centre of curvature.
(d) When object is kept at a distance greater than its radius of curvature.

Q. The real image formed by a concave mirror is smaller than the object if the object is:

(a) between centre of curvature and focus
(b) at a distance greater than radius of curvature
(c) at a distance equal to radius of curvature
(d) at a distance equal to focal length

Q. Under which of the conditions a concave mirror can form a real image larger than the actual object?

(a) When the object is kept at a distance equal to its radius of curvature.
(b) When object is kept at a distance less than its focal length.
(c) When object is placed between the focus and centre of curvature.
(d) When object is kept at a distance greater than its radius of curvature.

Q. When an object is placed between the centre of curvature and the focus of a concave mirror, its image will be:

Q. The distance between an object placed beyond center of curvature of a concave mirror and its image is d. If we move the object away from the mirror, the distance between object and image will

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An object is placed at the centre of curvature of a concave mirror. The distance between its image and the pole is:

The correct option is C equal to 2fGiven: u=−2f f=−f (concave mirror)To find : vSolution: From mirror formula1v+1u=1f1v−1−2f=−1f1v=−12fv=−2f

The correct option is C equal to 2f
Given: $u = - 2 f$ $f = - f$ (concave mirror)
To find : $v$
Solution: From mirror formula
$\frac{1}{v} + \frac{1}{u} = \frac{1}{f}$
$\frac{1}{v} - \frac{1}{- 2 f} = \frac{- 1}{f}$
$\frac{1}{v} = \frac{- 1}{2 f}$
$v = - 2 f$