An object is placed on the principal axis of a concave mirror at a distance of $60 c m$ . If the focal length of the concave mirror is $40 c m$ then the magnification obtained is equal to:

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Solution

The correct option is B $- 2$
From mirror formula $1 / f = 1 / v + 1 / u$ ,
Given, $u = 60 c m, f = 40 c m$
Putting the values in the equation, we get, $v = 120$ cm. So, magnification $m = v / u = 120 / 60 = 2$

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An object is placed on the principal axis of a concave mirror at a distance of 60 cm. If the focal length of the concave mirror is 40 cm then the magnification obtained is equal to:

The correct option is B −2From mirror formula 1/f=1/v+1/u, Given, u=60 cm,f=40 cm Putting the values in the equation, we get, v=120 cm. So, magnification m=v/u=120/60=2

An object is placed on the principal axis of a concave mirror at a distance of $60 c m$ . If the focal length of the concave mirror is $40 c m$ then the magnification obtained is equal to:

The correct option is B $- 2$
From mirror formula $1 / f = 1 / v + 1 / u$ ,
Given, $u = 60 c m, f = 40 c m$
Putting the values in the equation, we get, $v = 120$ cm. So, magnification $m = v / u = 120 / 60 = 2$