wiz-icon
MyQuestionIcon
MyQuestionIcon
2
You visited us 2 times! Enjoying our articles? Unlock Full Access!
Question

An object is placed on the principal axis of a concave mirror. Its real image is formed at a point that is 10 cm more distant from the mirror than the object. If the focal length of the mirror 12 cm. The magnification of the image is:

A
2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
- 1.5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1.5
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
- 2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B - 1.5
Given:
Focal length, f=12 cm
Object distance =u
Image distance (v) is 10 cm more than the object distance v=(u+10). Real images for concave mirrors are formed on the same side as the object for concave mirrors.
Using mirror formula,
1u+1v=1f
1u+1(u+10)=112
Simplifying,
u214u120=0
u220u+6u120=0
(u20)(u+6)=0
Object distance is taken as u. Hence, u is positive.
u=20 cm
Hence, image distance is:
v=30 cm
Magnification is given by:
m=Image DistanceObject Distance
m=3020=1.5

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Lens Formula, Magnification and Power of Lens
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon