CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

An object is placed on the surface of a smooth inclined plane of inclination θ. It takes time t to reach the bottom. If the same object is allowed to slide down a rough inclined plane of same inclination θ, it takes times nth to reach the bottom where n number greater than 1. The coefficient of friction μ is given by:

A
μ=tanθ(11/n2)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
μ=cotθ(11/n2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
μ=tanθ(11/n2)1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
μ=cotθ(11/n2)1/2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B μ=tanθ(11/n2)
Van=2Lg(sinθμcosθ)(1)
Va=2Lgsinθ(2)
By putting equ(2) in eq(1) we get
2Lgsinθn=2Lg(sinθμcosθ)
2Lgsinθn2=2Lg(sinθμcosθ)
sinθn2=sinθμcosθ
μcosθ=sinθsinθn2
μcosθ=sinθ(11n2)
μ=tanθ(11n2)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Friction: A Quantitative Picture
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon