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Question

An object is present on the principal axis of a concave mirror at a distance of 30 cm from it. The focal length of the mirror is 20 cm. If the object starts moving with velocity 2 cm/s perpendicular to the principal axis, then:


A
Image moves with 4 cm/s below the principal axis.
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B
Image moves with 8 cm/s above the principal axis.
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C
Image moves with 8 cm/s below the principal axis.
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D
Image moves with 4 cm/s above the principal axis.
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Solution

The correct option is A Image moves with 4 cm/s below the principal axis.
Given that
u=30 cm; f=20 cm; Vo=2 cm/s
where Vo speed of object

By using mirror formula,
1v+1u=1f

1v=1f1u=120130

v=60 cm

Magnification of the mirror is
m=vu=(60)30
m=2

Velocity of image perpendicular to principal axis
=m×Vo
=2×2=4 cm/s
Negative sign indicates velocity in downward direction i.e below the principal axis.

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