An object is present on the principal axis of a concave mirror at a distance of 30cm from it. The focal length of the mirror is 20cm. If the object starts moving with velocity 2cm/s perpendicular to the principal axis, then:
A
Image moves with 4cm/s below the principal axis.
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
Image moves with 8cm/s above the principal axis.
No worries! Weāve got your back. Try BYJUāS free classes today!
C
Image moves with 8cm/s below the principal axis.
No worries! Weāve got your back. Try BYJUāS free classes today!
D
Image moves with 4cm/s above the principal axis.
No worries! Weāve got your back. Try BYJUāS free classes today!
Open in App
Solution
The correct option is A Image moves with 4cm/s below the principal axis. Given that u=−30cm;f=−20cm;Vo=2cm/s
where Vo→ speed of object
By using mirror formula, 1v+1u=1f
⇒1v=1f−1u=1−20−1−30
⇒v=−60cm
Magnification of the mirror is m=−vu=−(−60)−30 ⇒m=−2
Velocity of image perpendicular to principal axis =m×Vo =−2×2=−4cm/s
Negative sign indicates velocity in downward direction i.e below the principal axis.