Question

An object is projected from ground with speed u at angle theta with horizontal. The radius of curvature of its trajectory at maximum height from ground is?

Answer 1

Dear Student,
$$\begin{gathered} Radiusofcurvatureoftrajectoryisgivenby \\ r=\frac{{\left(1+{\left({\displaystyle \frac{dy}{dx}}\right)}^2\right)}^{3/2}}{\left|{\displaystyle \frac{d^{2}y}{d{x}^2}}\right|} \\ atmaximumheight\frac{dy}{dx}=0 \\ so \\ r=\infty \end{gathered}$$
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