An object is projected vertically upward with speed $\sqrt{g R},$ where R is radius of earth and g is acceleration due to gravity on surface of earth, Find the maximum attained by it.

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Solution

$v^{2} - u^{2} = 2 a s$ Taking down words as -ive
$v = 0 u = - \sqrt{g} R S = ? a = - g$
$0 - (\sqrt{- g R})^{2} = 2 (- g) (s) = - g R = - 2 g S$
$S : R / 2$

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