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Byju's Answer
Standard XII
Physics
Acceleration in 2D
An object is ...
Question
An object is projected with velocity
→
v
0
=
15
^
i
+
20
^
j
. Considering x along horizontal axis and y along vertical axis. Find its velocity after
2
s
.
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Solution
→
v
0
=
15
^
i
+
20
^
j
v
0
x
=
15
m
/
s
v
0
y
=
20
m
/
s
after time
t
=
2
s
e
c
v
y
=
v
o
y
−
g
t
=
20
−
2
×
10
=
0
m
/
s
v
x
=
v
o
x
=
15
m
/
s
so velocity after
2
sec
=
15
^
i
+
0
^
j
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