An object is put one by one in three liquids having different densities. The object floats with $\frac{1}{9}$ , $\frac{2}{11}$ and $\frac{3}{7}$ parts of their volumes outside the liquid surface in liquids of densities $d_{1}$ , $d_{2}$ and $d_{3}$ respectively. Which of the following statement is correct?

d_{1} > d_{2} > d_{3}

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d_{1} > d_{2} < d_{3}

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d_{1} < d_{2} > d_{3}

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d_{1} < d_{2} < d_{3}

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Solution

The correct option is A $d_{1} > d_{2} > d_{3}$
The lesser the density of the fluid, the more is the buoyant force acting in an upward direction. And more is the part of the body that floats outside the liquid surface, so the order of density of the three given fluids will be $d_{1} > d_{2} > d_{3}$ .

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Similar questions

\frac{1}{9}

\frac{2}{11}

\frac{3}{7}

d_{1}

d_{2}

d_{3}

\frac{1}{9}, \frac{2}{11} and \frac{3}{7}

\frac{1}{9}, \frac{2}{11}

\frac{3}{7}

d_{1}, d_{2}

d_{3}

A body weighs $W_{1}$ in a liquid of density $d_{1}$ and $W_{2}$ in a liquid of density $d_{2}$ . What is the weight in a liquid of density $d_{3}$ ?

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