An object is resting at the bottom of two strings which are inclined at an angle of $120^{\circ}$ with each other. Each string can withstand a tension of 20 $N$ The maximum weight of the object that can be sustained without breaking the string is

N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\sqrt{2} N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

N

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B 20 $N$
Given $T = 20 N$
Free body diagram of mass.m
For vertical cquilibrimm. $T cos 60^{\circ} + T cos 60^{\circ} = m g$
m g=T=20 N

Max weight =20 N

Suggest Corrections

Similar questions

An object is resting at the bottom of two strings which are inclined at an angle of $120^{\circ}$ with each other. Each string can withstand a tension of $20 N$ . The maximum weight of the object that can be sustained without breaking the strings is

Q. An object is resting at the bottom of two strings which are inclined at an angle of

120^{\circ}

with each other. Each string can withstand a tension of

20 N

. The maximum weight of the object that can be sustained without breaking the strings is

A stone of mass 5 kg is attached to a string of 10 m length and is whirled in a horizontal circle. The string can withstand a maximum tension of 160 N. The maximum velocity of revolution that can be given to the stone without breaking the string is

Q. Q. A stone of mass 4 kg is attached to a string of length of whirled in a horizontal circle. A circle can withstand a tension 160 N. Calculate the maximum velocity that can be given to a stone without breaking the string.

Q. A bob of mass

500 g

attached to a light inextensible string revolving vertically in a radius

R

is given an initial velocity

v = \sqrt{7 g R}

at the bottom most point. The tension in the string at the bottom most point is

Join BYJU'S Learning Program

An object is resting at the bottom of two strings which are inclined at an angle of 120∘ with each other. Each string can withstand a tension of 20N The maximum weight of the object that can be sustained without breaking the string is

The correct option is B 20NGiven T=20N Free body diagram of mass.m For vertical cquilibrimm. Tcos60∘+Tcos60∘=mg m g=T=20 N Max weight =20 N

An object is resting at the bottom of two strings which are inclined at an angle of $120^{\circ}$ with each other. Each string can withstand a tension of 20 $N$ The maximum weight of the object that can be sustained without breaking the string is

The correct option is B 20 $N$
Given $T = 20 N$
Free body diagram of mass.m
For vertical cquilibrimm. $T cos 60^{\circ} + T cos 60^{\circ} = m g$
m g=T=20 N

Max weight =20 N